What is the solution for (x^2+1)(dy)/(dx)=x(y^2+1) ?

The solution for (x^2+1)(dy)/(dx)=x(y^2+1) is y=tan(1/2 ln(x^2+1)+c_{1})

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(x^2+1)(dy)/(dx)=x(y^2+1)

(x^{2} + 1) \frac{d y}{d x} = x (y^{2} + 1)

y = tan (\frac{1}{2} ln (x^{2} + 1) + c_{1})

Solution steps

(x^{2} + 1) \frac{d y}{d x} = x (y^{2} + 1)

Solve separable ODE:

y = tan (\frac{1}{2} ln (x^{2} + 1) + c_{1})

y = tan (\frac{1}{2} ln (x^{2} + 1) + c_{1})

x^{2} - 6 x - 7, - x^{2} + 2 x + 3

\int 5 sin^{5} (x) cos (x) d x

x \to - 1 + lim (8 x^{2} + 5 m)

n = 1 \sum \infty (- 1)^{n + 1} \frac{2}{3 ^{n}}

x \to 6 lim (8)

What is the solution for (x^2+1)(dy)/(dx)=x(y^2+1) ?
The solution for (x^2+1)(dy)/(dx)=x(y^2+1) is y=tan(1/2 ln(x^2+1)+c_{1})