What is the derivative of 1/8 x^2 ?

The derivative of 1/8 x^2 is x/4

What is the first derivative of 1/8 x^2 ?

The first derivative of 1/8 x^2 is x/4

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\frac{d}{d x} (\frac{1}{8} x^{2})

\frac{x}{4}

Solution steps

\frac{d}{d x} (\frac{1}{8} x^{2})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{8} \frac{d}{d x} (x^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{8} \cdot 2 x^{2 - 1}

Simplify

\frac{1}{8} \cdot 2 x^{2 - 1} : \frac{x}{4}

= \frac{x}{4}

\int_{0}^{1} (1 - x)^{2} d x

\frac{\partial}{\partial x} (- y^{2} sin (x y^{2}))

\frac{d}{d x} ((x - 1)^{4})

\int sin^{3} (θ) cos^{8} (θ) d θ

\int \frac{3}{3 sin ( x ) - 4 cos ( x )} d x

What is the derivative of 1/8 x^2 ?
The derivative of 1/8 x^2 is x/4
What is the first derivative of 1/8 x^2 ?
The first derivative of 1/8 x^2 is x/4