What is the derivative of x^2+6x+3 ?

The derivative of x^2+6x+3 is 2x+6

What is the first derivative of x^2+6x+3 ?

The first derivative of x^2+6x+3 is 2x+6

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derivative of

x^{2} + 6 x + 3

2 x + 6

Solution steps

\frac{d}{d x} (x^{2} + 6 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (3)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (3) = 0

= 2 x + 6 + 0

Simplify

= 2 x + 6

\frac{d}{d x} (3 \frac{1 + x ^{3}}{1 - x ^{3}})

x \to 8 + lim (ln (x^{2} - 64))

\frac{\partial}{\partial x} (x + \frac{1}{2} y)

\frac{1}{1 - x}, 1.1

\frac{d y}{d x}, y = 1.1 x + 0.077 x^{2}

What is the derivative of x^2+6x+3 ?
The derivative of x^2+6x+3 is 2x+6
What is the first derivative of x^2+6x+3 ?
The first derivative of x^2+6x+3 is 2x+6