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Popular >

y^'-2y=5

Solution

y^{^{'}} - 2 y = 5

Solution

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{5}{2}

Solution steps

y^{'} (t) - 2 y = 5

Solve separable ODE:

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{5}{2}

y = \frac{e ^{2 t + c_{1}}}{2} - \frac{5}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'-2y=5 ?
The solution for y^'-2y=5 is y=(e^{2t+c_{1}})/2-5/2