What is the solution for (dy)/(dx)=6+sqrt(y-6x+4) ?

The solution for (dy)/(dx)=6+sqrt(y-6x+4) is y=(x^2+c_{1}^2)/4+(c_{1}x)/2+6x-4

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(dy)/(dx)=6+sqrt(y-6x+4)

\frac{d y}{d x} = 6 + y - 6 x + 4

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} + 6 x - 4

Solution steps

\frac{d y}{d x} = 6 + y - 6 x + 4

Solve using substitution:

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} + 6 x - 4

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} + 6 x - 4

\int_{0}^{4} - x^{2} + 4 x d x

arccos (5 x^{8})

\frac{d}{d x} (\frac{7 x ^{2} - 1}{x})

y^{^{''}} + 4 y = 0, y (0) = 1, y^{^{'}} (0) = 4

\frac{d y}{d x} = 32 x^{3} y^{3}, y (0) = k

What is the solution for (dy)/(dx)=6+sqrt(y-6x+4) ?
The solution for (dy)/(dx)=6+sqrt(y-6x+4) is y=(x^2+c_{1}^2)/4+(c_{1}x)/2+6x-4