What is the derivative of x^4+cos(x+1) ?

The derivative of x^4+cos(x+1) is 4x^3-sin(x)

What is the first derivative of x^4+cos(x+1) ?

The first derivative of x^4+cos(x+1) is 4x^3-sin(x)

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\frac{d}{d x} (x^{4} + cos (x) + 1)

4 x^{3} - sin (x)

Solution steps

\frac{d}{d x} (x^{4} + cos (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{4}) + \frac{d}{d x} (cos (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{4}) = 4 x^{3}

\frac{d}{d x} (cos (x)) = - sin (x)

\frac{d}{d x} (1) = 0

= 4 x^{3} - sin (x) + 0

Simplify

= 4 x^{3} - sin (x)

\int \frac{( 16 - 9 x ^{2} ) ^{\frac{3}{2}}}{x ^{6}} d x

\int \frac{16}{( x + 2 ) ^{2}} d x

y^{^{'}} = y + x y

n = 1 \sum \infty (\frac{( 3 n - 1 )}{( 3 n )})^{n^{2}}

tan (x) sin^{2} (y) d x + cos^{2} (x) cot (y) d y = 0

What is the derivative of x^4+cos(x+1) ?
The derivative of x^4+cos(x+1) is 4x^3-sin(x)
What is the first derivative of x^4+cos(x+1) ?
The first derivative of x^4+cos(x+1) is 4x^3-sin(x)