What is the solution for (dy)/(dx)=e^4x+7y ?

The solution for (dy)/(dx)=e^4x+7y is y=-(e^4x)/7-(e^4)/(49)+c_{1}e^{7x}

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(dy)/(dx)=e^4x+7y

\frac{d y}{d x} = e^{4} x + 7 y

y = - \frac{e ^{4} x}{7} - \frac{e ^{4}}{49} + c_{1} e^{7 x}

Solution steps

\frac{d y}{d x} = e^{4} x + 7 y

Solve linear ODE:

y = - \frac{e ^{4} x}{7} - \frac{e ^{4}}{49} + c_{1} e^{7 x}

y = - \frac{e ^{4} x}{7} - \frac{e ^{4}}{49} + c_{1} e^{7 x}

\int x 3 x^{2} - 6 d x

\int \frac{3}{5 x ^{\frac{2}{5}}} d x

x \to 2 lim (\frac{2 x ^{2} - 5 x + 2}{x ^{3} - 2 x ^{2}})

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\frac{\partial}{\partial x} (x^{4} - 8 x y - 5 y^{2})

What is the solution for (dy)/(dx)=e^4x+7y ?
The solution for (dy)/(dx)=e^4x+7y is y=-(e^4x)/7-(e^4)/(49)+c_{1}e^{7x}