What is (\partial)/(\partial x)(-2(1-x)-40x(y-x^2)) ?

The answer to (\partial)/(\partial x)(-2(1-x)-40x(y-x^2)) is 2-40(y-3x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(-2(1-x)-40x(y-x^2))

\frac{\partial}{\partial x} (- 2 (1 - x) - 40 x (y - x^{2}))

2 - 40 (y - 3 x^{2})

Solution steps

\frac{\partial}{\partial x} (- 2 (1 - x) - 40 x (y - x^{2}))

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial x} (2 (1 - x)) - \frac{\partial}{\partial x} (40 x (y - x^{2}))

\frac{\partial}{\partial x} (2 (1 - x)) = - 2

\frac{\partial}{\partial x} (40 x (y - x^{2})) = 40 (y - 3 x^{2})

= - (- 2) - 40 (y - 3 x^{2})

Simplify

= 2 - 40 (y - 3 x^{2})

\frac{d}{d x} (e (- x))

\int_{0.2}^{0.4} 300 x d x

\int \frac{x ^{2} - 4}{x} d x

(4 + ln (x))^{7}

\frac{d y}{d t} + e^{t} y = - 6 e^{t}

What is (\partial)/(\partial x)(-2(1-x)-40x(y-x^2)) ?
The answer to (\partial)/(\partial x)(-2(1-x)-40x(y-x^2)) is 2-40(y-3x^2)