What is the derivative of 4x^3+3x ?

The derivative of 4x^3+3x is 12x^2+3

What is the first derivative of 4x^3+3x ?

The first derivative of 4x^3+3x is 12x^2+3

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\frac{d}{d x} (4 x^{3} + 3 x)

12 x^{2} + 3

Solution steps

\frac{d}{d x} (4 x^{3} + 3 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{3}) + \frac{d}{d x} (3 x)

\frac{d}{d x} (4 x^{3}) = 12 x^{2}

\frac{d}{d x} (3 x) = 3

= 12 x^{2} + 3

\int_{- 1}^{7} (2 x + 7) - (x^{2} - 4 x) d x

\int \frac{1}{- csc ( y )} d y

f (x) = - \frac{x + 3 arcsin ( x )}{4}

\frac{d}{d x} (e^{3 x} cos (3 x))

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What is the derivative of 4x^3+3x ?
The derivative of 4x^3+3x is 12x^2+3
What is the first derivative of 4x^3+3x ?
The first derivative of 4x^3+3x is 12x^2+3