What is the sum from n=1 to infinity of 8/(n^5) ?

The sum from n=1 to infinity of 8/(n^5) is converges

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sum from n=1 to infinity of 8/(n^5)

n = 1 \sum \infty \frac{8}{n ^{5}}

converges

Solution steps

n = 1 \sum \infty \frac{8}{n ^{5}}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= 8 \cdot n = 1 \sum \infty \frac{1}{n ^{5}}

Apply p-Series Test:

converges

= 8 converges

= converges

e^{- 2 x}

y = (x + x^{- 1})^{3}

\frac{d}{d x} ((x + 2)^{\frac{1}{2}})

\frac{\partial}{\partial x} (ln (x^{2} + y - 5))

\frac{d y}{d x} + y = 5 sin (2 x)

What is the sum from n=1 to infinity of 8/(n^5) ?
The sum from n=1 to infinity of 8/(n^5) is converges