What is the integral of (x+3)/(x-2) ?

The integral of (x+3)/(x-2) is x-2+5ln|x-2|+C

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integral of (x+3)/(x-2)

\int \frac{x + 3}{x - 2} d x

x - 2 + 5 ln ∣ x - 2 ∣ + C

Solution steps

\int \frac{x + 3}{x - 2} d x

Apply u-substitution

: \int \frac{u + 5}{u} d u

= \int \frac{u + 5}{u} d u

Expand

\frac{u + 5}{u} : 1 + \frac{5}{u}

= \int 1 + \frac{5}{u} d u

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u + \int \frac{5}{u} d u

\int 1 d u = u

\int \frac{5}{u} d u = 5 ln ∣ u ∣

= u + 5 ln ∣ u ∣

Substitute back

u = x - 2

= x - 2 + 5 ln ∣ x - 2 ∣

Add a constant to the solution

= x - 2 + 5 ln ∣ x - 2 ∣ + C

\frac{t ^{2}}{t - 2}

\int (6 x^{5} + 7 x) d x

\int x - x^{2} + x d x

\frac{d y}{d x} = \frac{y ^{2}}{e ^{x}}, y (0) = - 2

y = x^{2}, (0, - 4)

What is the integral of (x+3)/(x-2) ?
The integral of (x+3)/(x-2) is x-2+5ln|x-2|+C