What is the integral from 0 to pi/4 of sin(x) ?

The integral from 0 to pi/4 of sin(x) is -1/(sqrt(2))+1

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integral from 0 to pi/4 of sin(x)

\int_{0}^{\frac{π}{4}} sin (x) d x

- \frac{1}{2} + 1

Decimal Notation

0.29289 \dots

Solution steps

\int_{0}^{\frac{π}{4}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{0}^{\frac{π}{4}}

Compute the boundaries:

- \frac{1}{2} + 1

= - \frac{1}{2} + 1

\frac{48}{( 1 - x ) ^{4}}

\frac{d ^{2}}{d x ^{2}} ((2 x^{2} + 7)^{5})

f (x) = cos^{2} (x) + sin^{2} (x)

y^{^{''}} - y^{^{'}} - 2 y = - 8 t + 8 t^{2}

\int e^{2 t} cos (5 t) d t

What is the integral from 0 to pi/4 of sin(x) ?
The integral from 0 to pi/4 of sin(x) is -1/(sqrt(2))+1