What is (\partial)/(\partial y)(2x^3y+4) ?

The answer to (\partial)/(\partial y)(2x^3y+4) is 2x^3

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(\partial)/(\partial y)(2x^3y+4)

\frac{\partial}{\partial y} (2 x^{3} y + 4)

2 x^{3}

Solution steps

\frac{\partial}{\partial y} (2 x^{3} y + 4)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2 x^{3} y) + \frac{\partial}{\partial y} (4)

\frac{\partial}{\partial y} (2 x^{3} y) = 2 x^{3}

\frac{\partial}{\partial y} (4) = 0

= 2 x^{3} + 0

Simplify

= 2 x^{3}

\int (x^{\frac{3}{2}} + 1)^{2} d x

f (x) = sin (sin (sin (x)))

\frac{d y}{d x}, e^{x y} + x^{2} - y^{2} = 12

\frac{\partial}{\partial θ} (sin (θ))

\int e^{- x} + 4^{x} d x

What is (\partial)/(\partial y)(2x^3y+4) ?
The answer to (\partial)/(\partial y)(2x^3y+4) is 2x^3