What is the tangent of f(x)=(4x+5)/(x-1),\at x=2 ?

The tangent of f(x)=(4x+5)/(x-1),\at x=2 is y=-9x+31

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=(4x+5)/(x-1),\at x=2

tangent of

f (x) = \frac{4 x + 5}{x - 1}, at x = 2

y = - 9 x + 31

Solution steps

Find the tangent point:

(2, 13)

Find the slope of

f (x) = \frac{4 x + 5}{x - 1} : \frac{df ( x )}{d x} = - \frac{9}{( x - 1 ) ^{2}}

Compute the slope of

f (x) = \frac{4 x + 5}{x - 1}

x = 2 : m = - 9

Find the line with slope m=

- 9

and passing through

(2, 13) : y = - 9 x + 31

y = - 9 x + 31

x \to 0 lim (\frac{sin ( 5 x )}{6 x})

f (x) = 3 sec (5 x)

\frac{\partial}{\partial x} (\frac{17}{2} x^{4} y)

f (x) = x^{2} + x, at x = 1

\frac{1 - 6 t}{5 + t}

What is the tangent of f(x)=(4x+5)/(x-1),\at x=2 ?
The tangent of f(x)=(4x+5)/(x-1),\at x=2 is y=-9x+31