What is the derivative of 1-e^{3x} ?

The derivative of 1-e^{3x} is -3e^{3x}

What is the first derivative of 1-e^{3x} ?

The first derivative of 1-e^{3x} is -3e^{3x}

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\frac{d}{d x} (1 - e^{3 x})

- 3 e^{3 x}

Solution steps

\frac{d}{d x} (1 - e^{3 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (e^{3 x})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (e^{3 x}) = e^{3 x} \cdot 3

= 0 - e^{3 x} \cdot 3

Simplify

= - 3 e^{3 x}

\int_{0}^{2} x^{2} (1 - 0.5 x) d x

\int_{1}^{2} \frac{x ^{2} - 1}{x} d x

n = 1 \sum \infty \frac{1}{3 ^{n} + 2}

t cos (2 t)

k = 0 \sum \infty (\frac{e}{10})^{k}

What is the derivative of 1-e^{3x} ?
The derivative of 1-e^{3x} is -3e^{3x}
What is the first derivative of 1-e^{3x} ?
The first derivative of 1-e^{3x} is -3e^{3x}