What is the d/(dt)(t^2sin(wt)) ?

The d/(dt)(t^2sin(wt)) is 2tsin(wt)+cos(wt)wt^2

What is the first d/(dt)(t^2sin(wt)) ?

The first d/(dt)(t^2sin(wt)) is 2tsin(wt)+cos(wt)wt^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d t} (t^{2} sin (wt))

2 t sin (wt) + cos (wt) w t^{2}

Solution steps

\frac{d}{d t} (t^{2} sin (wt))

Treat

w

as a constant

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t^{2}, g = sin (wt)

= \frac{d}{d t} (t^{2}) sin (wt) + \frac{d}{d t} (sin (wt)) t^{2}

\frac{d}{d t} (t^{2}) = 2 t

\frac{d}{d t} (sin (wt)) = cos (wt) w

= 2 t sin (wt) + cos (wt) w t^{2}

\int \frac{1}{( x ^{2} + 3 ) ^{\frac{3}{2}}} d x

\int \frac{1}{9 x ^{2} + 36 x + 35} d x

y = \frac{8 x}{x ^{2} - 1}, (3, 3)

y^{^{''}} + 625 y = sec (25 x)

e^{5 x}

What is the d/(dt)(t^2sin(wt)) ?
The d/(dt)(t^2sin(wt)) is 2tsin(wt)+cos(wt)wt^2
What is the first d/(dt)(t^2sin(wt)) ?
The first d/(dt)(t^2sin(wt)) is 2tsin(wt)+cos(wt)wt^2