What is (\partial)/(\partial u)(u-uv) ?

The answer to (\partial)/(\partial u)(u-uv) is 1-v

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(\partial)/(\partial u)(u-uv)

\frac{\partial}{\partial u} (u - uv)

1 - v

Solution steps

\frac{\partial}{\partial u} (u - uv)

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (u) - \frac{\partial}{\partial u} (uv)

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (uv) = v

= 1 - v

\frac{2}{x ^{4}}

f (y) = y ln (1 + e^{y})

\int \frac{cos ( x )}{sin ^{3} ( x ) - cos ^{3} ( x )} d x

\frac{d}{d x} (sin (2 x) + 2 x cos (2 x))

f (x) = \frac{e ^{x}}{1 + e ^{x}}

What is (\partial)/(\partial u)(u-uv) ?
The answer to (\partial)/(\partial u)(u-uv) is 1-v