What is the solution for y^'=(5x^6e^{y/x}+x^4y^2)/(x^5y) ?

The solution for y^'=(5x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((5ln(x)+c_{1})/e)x-x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=(5x^6e^{y/x}+x^4y^2)/(x^5y)

y^{^{'}} = \frac{5 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

y = - W (\frac{5 ln ( x ) + c _{1}}{e}) x - x

Solution steps

y^{'} (x) = \frac{5 x ^{6} e ^{\frac{y}{x}} + x ^{4} y ^{2}}{x ^{5} y}

Solve using substitution:

y = - W (\frac{5 ln ( x ) + c _{1}}{e}) x - x

y = - W (\frac{5 ln ( x ) + c _{1}}{e}) x - x

(e^{x} + 1)^{7}

8 y^{^{'}} + t y = 7

\frac{1}{x - 1}

\int \frac{8 z ^{2} + 2}{2 z ^{3} + z}

What is the solution for y^'=(5x^6e^{y/x}+x^4y^2)/(x^5y) ?
The solution for y^'=(5x^6e^{y/x}+x^4y^2)/(x^5y) is y=-\W((5ln(x)+c_{1})/e)x-x