What is the derivative of (x^2^3) ?

The derivative of (x^2^3) is 6x^5

What is the first derivative of (x^2^3) ?

The first derivative of (x^2^3) is 6x^5

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\frac{d}{d x} ((x^{2})^{3})

6 x^{5}

Solution steps

\frac{d}{d x} ((x^{2})^{3})

Simplify

(x^{2})^{3} : x^{6}

= \frac{d}{d x} (x^{6})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 6 x^{6 - 1}

Simplify

= 6 x^{5}

\frac{d}{d x} (\frac{sec ( x )}{1 + tan ( x )})

x y^{^{''}} + 4 y^{^{'}} = 0

\int_{0}^{2} arctan (\frac{x}{2}) d x

\frac{d}{d x} (- 0.0006 x (x - 15)^{2} (x - 40))

y = x (7 x + 3)^{\frac{1}{3}}

What is the derivative of (x^2^3) ?
The derivative of (x^2^3) is 6x^5
What is the first derivative of (x^2^3) ?
The first derivative of (x^2^3) is 6x^5