What is the limit as x approaches 0+of 3x^x ?

The limit as x approaches 0+of 3x^x is 3

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limit as x approaches 0+of 3x^x

x \to 0 + lim (3 x^{x})

3

Solution steps

x \to 0 + lim (3 x^{x})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 3 \cdot x \to 0 + lim (x^{x})

Apply exponent rules

= 3 \cdot x \to 0 + lim (e^{x l n (x)})

Apply the Limit Chain Rule:

1

= 3 \cdot 1

Simplify

= 3

x \to + 0 lim (x^{3} cos (\frac{π}{x}))

\frac{\partial}{\partial x} (sin (2 x y))

\frac{\partial}{\partial x} (\frac{y - 2 x}{6 y - x})

y = ln (x^{4} sin^{2} (x))

y^{^{'}} = \frac{1}{x}

What is the limit as x approaches 0+of 3x^x ?
The limit as x approaches 0+of 3x^x is 3