What is the derivative of 16-1/625 x^2 ?

The derivative of 16-1/625 x^2 is -(2x)/(625)

What is the first derivative of 16-1/625 x^2 ?

The first derivative of 16-1/625 x^2 is -(2x)/(625)

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\frac{d}{d x} (16 - \frac{1}{625} x^{2})

- \frac{2 x}{625}

Solution steps

\frac{d}{d x} (16 - \frac{1}{625} x^{2})

Simplify

16 - \frac{1}{625} x^{2} : 16 - \frac{x ^{2}}{625}

= \frac{d}{d x} (16 - \frac{x ^{2}}{625})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (16) - \frac{d}{d x} (\frac{x ^{2}}{625})

\frac{d}{d x} (16) = 0

\frac{d}{d x} (\frac{x ^{2}}{625}) = \frac{2 x}{625}

= 0 - \frac{2 x}{625}

Simplify

= - \frac{2 x}{625}

2^{80}

x^{2} + y^{2} = 9

\int_{1}^{4} 6 x d x

\int (x^{3} + 1) d x

\frac{d}{d x} (\frac{d y}{d x}) + 3 y = 0

What is the derivative of 16-1/625 x^2 ?
The derivative of 16-1/625 x^2 is -(2x)/(625)
What is the first derivative of 16-1/625 x^2 ?
The first derivative of 16-1/625 x^2 is -(2x)/(625)