What is (\partial)/(\partial x)(sin(pi(2x-3y))) ?

The answer to (\partial)/(\partial x)(sin(pi(2x-3y))) is cos(pi(2x-3y))*2pi

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(\partial)/(\partial x)(sin(pi(2x-3y)))

\frac{\partial}{\partial x} (sin (π (2 x - 3 y)))

cos (π (2 x - 3 y)) \cdot 2 π

Solution steps

\frac{\partial}{\partial x} (sin (π (2 x - 3 y)))

Treat

y

as a constant

Apply the chain rule:

cos (π (2 x - 3 y)) \frac{\partial}{\partial x} (π (2 x - 3 y))

= cos (π (2 x - 3 y)) \frac{\partial}{\partial x} (π (2 x - 3 y))

\frac{\partial}{\partial x} (π (2 x - 3 y)) = 2 π

= cos (π (2 x - 3 y)) \cdot 2 π

x \to 0 + lim ((2 x^{2} + x)^{x})

x \to 3 lim (\frac{( x + 2 )}{x + 3})

e^{2 x}, x = 0

x \to 2 lim (- 4 x^{2} - 3 x + 6)

\int 6 t d t

What is (\partial)/(\partial x)(sin(pi(2x-3y))) ?
The answer to (\partial)/(\partial x)(sin(pi(2x-3y))) is cos(pi(2x-3y))*2pi