What is (\partial)/(\partial y)(5y-2x) ?

The answer to (\partial)/(\partial y)(5y-2x) is 5

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(\partial)/(\partial y)(5y-2x)

\frac{\partial}{\partial y} (5 y - 2 x)

5

Solution steps

\frac{\partial}{\partial y} (5 y - 2 x)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (5 y) - \frac{\partial}{\partial y} (2 x)

\frac{\partial}{\partial y} (5 y) = 5

\frac{\partial}{\partial y} (2 x) = 0

= 5 - 0

Simplify

= 5

2 y^{^{''}} + 8 y^{^{'}} + 80 y = 100 cos (8 t)

(2 x - 1) d x + (7 y + 5) d y = 0

\frac{d}{d x} (2 e^{x - 1})

\int tan (x) \cdot sec^{2} (x) d x

\frac{d}{d x} (cos^{2} (x) - 2 sin (x))

What is (\partial)/(\partial y)(5y-2x) ?
The answer to (\partial)/(\partial y)(5y-2x) is 5