What is the solution for y^{''}-2y+6=0 ?

The solution for y^{''}-2y+6=0 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}+3

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y^{''}-2y+6=0

y^{^{''}} - 2 y + 6 = 0

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + 3

Solution steps

y^{''} (t) - 2 y + 6 = 0

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + 3

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} + 3

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x \to π lim (\frac{tan ( x )}{sin ( 2 x )})

What is the solution for y^{''}-2y+6=0 ?
The solution for y^{''}-2y+6=0 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}+3