What is the limit as x approaches-4+of 1/(x^2-16) ?

The limit as x approaches-4+of 1/(x^2-16) is -infinity

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limit as x approaches-4+of 1/(x^2-16)

x \to - 4 + lim (\frac{1}{x ^{2} - 16})

- \infty

Solution steps

x \to - 4 + lim (\frac{1}{x ^{2} - 16})

For

x

approaching

- 4

from the right

, x > - 4 \Rightarrow x^{2} - 16 < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

\int \frac{1}{( 16 - x ^{2} ) ^{\frac{3}{2}}} d x

\int e^{\frac{x}{n}} d x

f (x) = \frac{1}{( 3 x ^{2} - 1 ) ^{2}}

f (x) = x^{2} + 3, (3, 12)

\int (3 x^{2} tan (y) - \frac{2 y ^{3}}{x ^{3}}) d x

What is the limit as x approaches-4+of 1/(x^2-16) ?
The limit as x approaches-4+of 1/(x^2-16) is -infinity