What is the derivative of x+|x| ?

The derivative of x+|x| is 1+x/(|x|)

What is the first derivative of x+|x| ?

The first derivative of x+|x| is 1+x/(|x|)

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derivative of

x + ∣ x ∣

1 + \frac{x}{∣ x ∣}

Solution steps

\frac{d}{d x} (x + ∣ x ∣)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (∣ x ∣)

\frac{d x}{d x} = 1

\frac{d}{d x} (∣ x ∣) = \frac{x}{∣ x ∣}

= 1 + \frac{x}{∣ x ∣}

((x + y)^{2}) d x + (2 x y + x^{2} - 8) d y = 0, y (1) = 1

\frac{\partial}{\partial y} (z)

x \to - 2 lim (10 x + 3)

\int (9 - x^{2})^{\frac{1}{2}} d x

sin (4 x)

What is the derivative of x+|x| ?
The derivative of x+|x| is 1+x/(|x|)
What is the first derivative of x+|x| ?
The first derivative of x+|x| is 1+x/(|x|)