What is the solution for xy^'= 1/(xy) ?

The solution for xy^'= 1/(xy) is y=sqrt(-2/x+c_{1)},y=-sqrt(-2/x+c_{1)}

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xy^'= 1/(xy)

x y^{^{'}} = \frac{1}{x y}

y = - \frac{2}{x} + c_{1}, y = - - \frac{2}{x} + c_{1}

Solution steps

x y^{'} (x) = \frac{1}{x y}

Solve separable ODE:

y = - \frac{2}{x} + c_{1}, y = - - \frac{2}{x} + c_{1}

y = - \frac{2}{x} + c_{1}, y = - - \frac{2}{x} + c_{1}

\int (\frac{x ^{3}}{1 + x ^{4}}) d x

\frac{\partial}{\partial x} (e^{4 x y} ln (7 y))

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What is the solution for xy^'= 1/(xy) ?
The solution for xy^'= 1/(xy) is y=sqrt(-2/x+c_{1)},y=-sqrt(-2/x+c_{1)}