What is the limit as x approaches 0+of e^{(-1/x)} ?

The limit as x approaches 0+of e^{(-1/x)} is 0

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limit as x approaches 0+of e^{(-1/x)}

x \to 0 + lim (e^{(- \frac{1}{x})})

0

Solution steps

x \to 0 + lim (e^{- \frac{1}{x}})

Apply the Limit Chain Rule:

0

= 0

h (t) = t^{\frac{3}{4}} - 4 t^{\frac{1}{4}}

\frac{d}{d t} (\frac{2}{t})

\frac{1}{3} (16 + x^{2})^{3}

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What is the limit as x approaches 0+of e^{(-1/x)} ?
The limit as x approaches 0+of e^{(-1/x)} is 0