What is the limit as x approaches 1-of (x+1)/(x^4-1) ?

The limit as x approaches 1-of (x+1)/(x^4-1) is -infinity

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limit as x approaches 1-of (x+1)/(x^4-1)

x \to 1 - lim (\frac{x + 1}{x ^{4} - 1})

- \infty

Solution steps

x \to 1 - lim (\frac{x + 1}{x ^{4} - 1})

Simplify

\frac{x + 1}{x ^{4} - 1} : \frac{1}{( x ^{2} + 1 ) ( x - 1 )}

= x \to 1 - lim (\frac{1}{( x ^{2} + 1 ) ( x - 1 )})

For

x

approaching

1

from the left

, x < 1 \Rightarrow (x^{2} + 1) (x - 1) < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

x^{2} y^{^{''}} - 2 x y^{^{'}} - 4 y = 0, y (1) = 0, y^{^{'}} (1) = - 5

\frac{d}{d x} (x^{4} - \frac{x ^{8}}{6} - x^{2} sin (x^{2}))

\int (5 x + 4)^{3} d x

\frac{\partial}{\partial x} (sin^{2} (t))

n = 0 \sum \infty \frac{n}{( \frac{3}{2} ) ^{n}}

What is the limit as x approaches 1-of (x+1)/(x^4-1) ?
The limit as x approaches 1-of (x+1)/(x^4-1) is -infinity