What is the derivative of 3x^2-x+5 ?

The derivative of 3x^2-x+5 is 6x-1

What is the first derivative of 3x^2-x+5 ?

The first derivative of 3x^2-x+5 is 6x-1

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\frac{d}{d x} (3 x^{2} - x + 5)

6 x - 1

Solution steps

\frac{d}{d x} (3 x^{2} - x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) - \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 6 x - 1 + 0

Simplify

= 6 x - 1

sin^{6} (x)

\int_{0}^{\frac{1}{3}} 2 arcsin (3 y) d y

\int 9 x e^{8 x} d x

\int (e^{- 3 x} - 1)^{2} d x

\frac{d y}{d x} - 2 y = 2 x

What is the derivative of 3x^2-x+5 ?
The derivative of 3x^2-x+5 is 6x-1
What is the first derivative of 3x^2-x+5 ?
The first derivative of 3x^2-x+5 is 6x-1