What is the derivative of 1/(3x^4) ?

The derivative of 1/(3x^4) is -4/(3x^5)

What is the first derivative of 1/(3x^4) ?

The first derivative of 1/(3x^4) is -4/(3x^5)

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derivative of

\frac{1}{3 x ^{4}}

- \frac{4}{3 x ^{5}}

Solution steps

\frac{d}{d x} (\frac{1}{3 x ^{4}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{3} \frac{d}{d x} (\frac{1}{x ^{4}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{3} \frac{d}{d x} (x^{- 4})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{3} (- 4 x^{- 4 - 1})

Simplify

\frac{1}{3} (- 4 x^{- 4 - 1}) : - \frac{4}{3 x ^{5}}

= - \frac{4}{3 x ^{5}}

\frac{d}{d x} (2 arctan (\frac{y}{x}))

(2) (1) \frac{d y}{d x} = 7

\int \frac{2 x - 1}{x} d x

x^{2} sin (4 x)

\frac{\partial}{\partial x} (6 x^{5} y^{6} + 8 x^{7} y^{8})

What is the derivative of 1/(3x^4) ?
The derivative of 1/(3x^4) is -4/(3x^5)
What is the first derivative of 1/(3x^4) ?
The first derivative of 1/(3x^4) is -4/(3x^5)