What is the integral of 6x^2\sqrt[3]{x} ?

The integral of 6x^2\sqrt[3]{x} is 6(1/3 x^3\sqrt[3]{x}-1/30 x^{10/3})+C

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integral of 6x^2\sqrt[3]{x}

Solution steps

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

Apply Integration By Parts

\int \frac{1}{9} x^{\frac{7}{3}} d x = \frac{1}{30} x^{\frac{10}{3}}

Add a constant to the solution

y = x^{3} - 3 x + 2, (4, 54)

\frac{s ^{2} + 12}{s ^{4} - 16}

\frac{d}{d x} (\frac{x ^{2}}{2 - x})

x \to 0 lim (sin (x) ln (x))

\int \frac{29 x ^{2}}{x ^{2} - 4} d x

What is the integral of 6x^2\sqrt[3]{x} ?
The integral of 6x^2\sqrt[3]{x} is 6(1/3 x^3\sqrt[3]{x}-1/30 x^{10/3})+C