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Popular >

integral of 1/8 t

Solution

\int \frac{1}{8} t d t

Solution

\frac{t ^{2}}{16} + C

Solution steps

\int \frac{1}{8} t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{8} \cdot \int t d t

Apply the Power Rule

: \frac{t ^{2}}{2}

= \frac{1}{8} \cdot \frac{t ^{2}}{2}

Simplify

\frac{1}{8} \cdot \frac{t ^{2}}{2} : \frac{t ^{2}}{16}

= \frac{t ^{2}}{16}

Add a constant to the solution

= \frac{t ^{2}}{16} + C

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xy^'+2y=-4sin(x)

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Frequently Asked Questions (FAQ)

What is the integral of 1/8 t ?
The integral of 1/8 t is (t^2)/(16)+C