What is the tangent of f(x)=tan(x),\at x= pi/4 ?

The tangent of f(x)=tan(x),\at x= pi/4 is y=2x+1-pi/2

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tangent of f(x)=tan(x),\at x= pi/4

tangent of

f (x) = tan (x), at x = \frac{π}{4}

y = 2 x + 1 - \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{4}, 1)

Find the slope of

f (x) = tan (x) : \frac{df ( x )}{d x} = sec^{2} (x)

Compute the slope of

f (x) = tan (x)

x = \frac{π}{4} : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{4}, 1) : y = 2 x + 1 - \frac{π}{2}

y = 2 x + 1 - \frac{π}{2}

f (x) = \frac{2 - 3 x - x ^{2}}{x ^{2} - 5}

\int x^{e} + \frac{2}{x} + sec^{2} (2 x) d x

x \to 0 lim (\frac{cos ( 7 x ) tan ( 7 x )}{x})

f (x) = (1 + x) cos (x), at x = 0

y = \frac{1}{3} x^{2} - 2 x + 4, (3, 1)

What is the tangent of f(x)=tan(x),\at x= pi/4 ?
The tangent of f(x)=tan(x),\at x= pi/4 is y=2x+1-pi/2