What is the sum from n=0 to infinity of (1/6)^n ?

The sum from n=0 to infinity of (1/6)^n is 6/5

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sum from n=0 to infinity of (1/6)^n

n = 0 \sum \infty (\frac{1}{6})^{n}

\frac{6}{5}

Solution steps

n = 0 \sum \infty (\frac{1}{6})^{n}

Apply Series Geometric Test:

\frac{6}{5}

= \frac{6}{5}

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What is the sum from n=0 to infinity of (1/6)^n ?
The sum from n=0 to infinity of (1/6)^n is 6/5