What is laplacetransform t+4 ?

The answer to laplacetransform t+4 is 1/(s^2)+4/s

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laplacetransform t+4

laplace transform

t + 4

\frac{1}{s ^{2}} + \frac{4}{s}

Solution steps

L {t + 4}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} + L {4}

L {t} : \frac{1}{s ^{2}}

L {4} : \frac{4}{s}

= \frac{1}{s ^{2}} + \frac{4}{s}

10 e^{- 10 t}

f (x) = ln (x^{4})

\int cos (\frac{1}{3} x) d x

\frac{1}{( s - 7 ) ^{3}}

n = 1 \sum \infty \frac{2 n}{n ^{2} + 1}

What is laplacetransform t+4 ?
The answer to laplacetransform t+4 is 1/(s^2)+4/s