What is the tangent of f(x)=x^2,(2,4) ?

The tangent of f(x)=x^2,(2,4) is y=4x-4

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tangent of f(x)=x^2,(2,4)

tangent of

f (x) = x^{2}, (2, 4)

y = 4 x - 4

Solution steps

Find the slope of

f (x) = x^{2} : \frac{df ( x )}{d x} = 2 x

Compute the slope of

f (x) = x^{2}

(2, 4) : m = 4

Find the line with slope m=

4

and passing through

(2, 4) : y = 4 x - 4

y = 4 x - 4

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