What is (\partial)/(\partial y)(-x^2y+cos(x)) ?

The answer to (\partial)/(\partial y)(-x^2y+cos(x)) is -x^2

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(\partial)/(\partial y)(-x^2y+cos(x))

\frac{\partial}{\partial y} (- x^{2} y + cos (x))

- x^{2}

Solution steps

\frac{\partial}{\partial y} (- x^{2} y + cos (x))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{\partial}{\partial y} (x^{2} y) + \frac{\partial}{\partial y} (cos (x))

\frac{\partial}{\partial y} (x^{2} y) = x^{2}

\frac{\partial}{\partial y} (cos (x)) = 0

= - x^{2} + 0

Simplify

= - x^{2}

x \to 2 lim (5 π)

(- 3, 7), (6, - 8)

x^{2} y^{^{'}} + \frac{4}{3} x y = 2 cos (2 x) y^{- \frac{1}{2}}

x \to 0 lim (\frac{1}{ln ( x + 1 )})

\int cos (\frac{x}{y}) d x

What is (\partial)/(\partial y)(-x^2y+cos(x)) ?
The answer to (\partial)/(\partial y)(-x^2y+cos(x)) is -x^2