What is the tangent of y=tan(x),\at x= pi/4 ?

The tangent of y=tan(x),\at x= pi/4 is y=2x+1-pi/2

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tangent of y=tan(x),\at x= pi/4

tangent of

y = tan (x), at x = \frac{π}{4}

y = 2 x + 1 - \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{4}, 1)

Find the slope of

y = tan (x) : \frac{d y}{d x} = sec^{2} (x)

Compute the slope of

y = tan (x)

x = \frac{π}{4} : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{4}, 1) : y = 2 x + 1 - \frac{π}{2}

y = 2 x + 1 - \frac{π}{2}

\int_{\frac{1}{7}}^{3} 14 x ln (7 x) d x

\frac{\partial}{\partial x} (\frac{5 y}{x ^{2} + 1})

\frac{d}{d x} (\frac{x + 1}{1 - x})

\int_{- 3}^{3} (\frac{27}{2} - \frac{3}{2} x^{2}) d x

x \to 0 - lim (\frac{x - 2}{x ^{2} - 4})

What is the tangent of y=tan(x),\at x= pi/4 ?
The tangent of y=tan(x),\at x= pi/4 is y=2x+1-pi/2