What is the integral of 1/100 x+10 ?

The integral of 1/100 x+10 is (x^2)/(200)+10x+C

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integral of 1/100 x+10

\int \frac{1}{100} x + 10 d x

\frac{x ^{2}}{200} + 10 x + C

Solution steps

\int \frac{1}{100} x + 10 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{1}{100} x d x + \int 10 d x

\int \frac{1}{100} x d x = \frac{x ^{2}}{200}

\int 10 d x = 10 x

= \frac{x ^{2}}{200} + 10 x

Add a constant to the solution

= \frac{x ^{2}}{200} + 10 x + C

\frac{\partial}{\partial x} (ln (x^{7} + y^{3}))

\int_{0}^{8} 1 + 9 x d x

\frac{\partial}{\partial x} (3 x + 5 y)

\frac{d}{d x} (\frac{x}{4 + x ^{2}})

x \to 0 lim (\frac{sin ( 9 x )}{sin ( 3 x )})

What is the integral of 1/100 x+10 ?
The integral of 1/100 x+10 is (x^2)/(200)+10x+C