What is the integral of-x^{1/2} ?

The integral of-x^{1/2} is -2/3 x^{3/2}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of-x^{1/2}

\int - x^{\frac{1}{2}} d x

- \frac{2}{3} x^{\frac{3}{2}} + C

Solution steps

\int - x^{\frac{1}{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int x^{\frac{1}{2}} d x

Apply the Power Rule

: \frac{2}{3} x^{\frac{3}{2}}

= - \frac{2}{3} x^{\frac{3}{2}}

Add a constant to the solution

= - \frac{2}{3} x^{\frac{3}{2}} + C

\int \frac{x}{x ^{4} + x ^{2} + 1} d x

\frac{d}{d x} (\frac{( x ^{2} - 1 ) ^{4}}{x ^{2} + 1})

x \to \infty lim (x^{2} - 9)

(x^{2} - 60) (2 x - 3)

\int \frac{x - 4}{x + 2} d x