en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of (2t+1)

Solution

\int (2 t + 1) d t

Solution

t^{2} + t + C

Solution steps

\int 2 t + 1 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 t d t + \int 1 d t

\int 2 t d t = t^{2}

\int 1 d t = t

= t^{2} + t

Add a constant to the solution

= t^{2} + t + C

Popular Examples

integral of (3x^3-2x^2+2x-4)/(-x^4-2x^2)

\int \frac{3 x ^{3} - 2 x ^{2} + 2 x - 4}{- x ^{4} - 2 x ^{2}} d x

81y^{''}+72y^'+16y=0,y(0)=2,y^'(0)=-1

81 y^{^{''}} + 72 y^{^{'}} + 16 y = 0, y (0) = 2, y^{^{'}} (0) = - 1

integral from 1 to 2 of (3/(x^2)-1)

\int_{1}^{2} (\frac{3}{x ^{2}} - 1) d x

(dy)/(dx)=(2x+y+1)/(4x+2y-5)

\frac{d y}{d x} = \frac{2 x + y + 1}{4 x + 2 y - 5}

limit as x approaches 0 of 5+4x-x^3

x \to 0 lim (5 + 4 x - x^{3})

Frequently Asked Questions (FAQ)

What is the integral of (2t+1) ?
The integral of (2t+1) is t^2+t+C