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Popular >

integral from 0 to 2 of (x+1)^2

Solution

\int_{0}^{2} (x + 1)^{2} d x

Solution

\frac{26}{3}

+1

Decimal Notation

8.66666 \dots

Solution steps

\int_{0}^{2} (x + 1)^{2} d x

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= \int_{0}^{2} x^{2} + 2 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x + \int_{0}^{2} 2 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 2 x d x = 4

\int_{0}^{2} 1 d x = 2

= \frac{8}{3} + 4 + 2

Simplify

\frac{8}{3} + 4 + 2 : \frac{26}{3}

= \frac{26}{3}

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(\partial)/(\partial x)(e^{-4x^2})

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\frac{d}{d x} (6 ln (x))

2x-1+(3y+7)((dy)/(dx))=0

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (x+1)^2 ?
The integral from 0 to 2 of (x+1)^2 is 26/3