What is laplacetransform t-2 ?

The answer to laplacetransform t-2 is 1/(s^2)-2/s

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laplacetransform t-2

laplace transform

t - 2

\frac{1}{s ^{2}} - \frac{2}{s}

Solution steps

L {t - 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {2}

L {t} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{1}{s ^{2}} - \frac{2}{s}

\frac{d y}{d x} = y (x y^{2} - 1)

\int (tan (x) + sec (x))^{2} d x

x \to \infty lim (\frac{x ^{3} - 4 x ^{2} + x + 6}{x + 1})

\frac{d y}{d x} = x^{2} - 1, y (0) = 1

\int 4 e^{4 x} sin (e^{4 x}) d x

What is laplacetransform t-2 ?
The answer to laplacetransform t-2 is 1/(s^2)-2/s