What is the tangent of f(x)=x^4,\at x=2 ?

The tangent of f(x)=x^4,\at x=2 is y=32x-48

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tangent of f(x)=x^4,\at x=2

tangent of

f (x) = x^{4}, at x = 2

y = 32 x - 48

Solution steps

Find the tangent point:

(2, 16)

Find the slope of

f (x) = x^{4} : \frac{df ( x )}{d x} = 4 x^{3}

Compute the slope of

f (x) = x^{4}

x = 2 : m = 32

Find the line with slope m=

32

and passing through

(2, 16) : y = 32 x - 48

y = 32 x - 48

\int (\frac{9 + x}{x})^{2} d x

\int - csc (2 x) cot (2 x) d x

(2, 3), (- 4, - 3)

h \to 0 lim (\frac{( 5 + h ) ^{4} - 625}{h})

y = ln (5) x^{3}

What is the tangent of f(x)=x^4,\at x=2 ?
The tangent of f(x)=x^4,\at x=2 is y=32x-48