What is the derivative of y=3x^2+6x+6 ?

The derivative of y=3x^2+6x+6 is 6x+6

What is the first derivative of y=3x^2+6x+6 ?

The first derivative of y=3x^2+6x+6 is 6x+6

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derivative of

y = 3 x^{2} + 6 x + 6

6 x + 6

Solution steps

\frac{d}{d x} (3 x^{2} + 6 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (6 x) + \frac{d}{d x} (6)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (6) = 0

= 6 x + 6 + 0

Simplify

= 6 x + 6

\int (x - 1)^{2} d x

\int sin^{5} (\frac{x}{2}) cos^{4} (\frac{x}{2}) d x

\frac{\partial}{\partial x} (y + x y)

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{2} + x + 1})

\frac{d}{d x} (x + y + z^{2})

What is the derivative of y=3x^2+6x+6 ?
The derivative of y=3x^2+6x+6 is 6x+6
What is the first derivative of y=3x^2+6x+6 ?
The first derivative of y=3x^2+6x+6 is 6x+6