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Popular >

y^'+(x+2)y^2=0

Solution

y^{^{'}} + (x + 2) y^{2} = 0

Solution

y = - \frac{2}{- x ^{2} - 4 x + c _{1}}

Solution steps

y^{'} (x) + (x + 2) y^{2} = 0

Solve separable ODE:

y = - \frac{2}{- x ^{2} - 4 x + c _{1}}

y = - \frac{2}{- x ^{2} - 4 x + c _{1}}

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Frequently Asked Questions (FAQ)

What is the solution for y^'+(x+2)y^2=0 ?
The solution for y^'+(x+2)y^2=0 is y=-2/(-x^2-4x+c_{1)}