What is (\partial)/(\partial x)(y^2-x*y) ?

The answer to (\partial)/(\partial x)(y^2-x*y) is -y

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(\partial)/(\partial x)(y^2-x*y)

\frac{\partial}{\partial x} (y^{2} - x \cdot y)

- y

Solution steps

\frac{\partial}{\partial x} (y^{2} - x y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (x y)

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (x y) = y

= 0 - y

Simplify

= - y

\int ln (2 - x) d x

\frac{d}{d x} (ln (x^{3} - 2 x^{2}))

\frac{d ^{2}}{d x ^{2}} (x^{\frac{5}{2}} e^{x})

\int cos (0)

\frac{d}{d x} ((3 x + 5)^{3})

What is (\partial)/(\partial x)(y^2-x*y) ?
The answer to (\partial)/(\partial x)(y^2-x*y) is -y