What is the integral of 2sin(θ) ?

The integral of 2sin(θ) is -2cos(θ)+C

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integral of 2sin(θ)

\int 2 sin (θ) d θ

- 2 cos (θ) + C

Solution steps

\int 2 sin (θ) d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int sin (θ) d θ

Use the common integral:

\int sin (θ) d θ = - cos (θ)

= 2 (- cos (θ))

Simplify

= - 2 cos (θ)

Add a constant to the solution

= - 2 cos (θ) + C

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 2

\frac{4}{3} π x^{3}

\frac{d}{d t} (e^{s i n (t)})

\frac{1 + x}{1 - x}

\frac{d}{d x} (\frac{2 x ^{3}}{3})