What is (\partial)/(\partial y)(3x^2+3y^2) ?

The answer to (\partial)/(\partial y)(3x^2+3y^2) is 6y

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(\partial)/(\partial y)(3x^2+3y^2)

\frac{\partial}{\partial y} (3 x^{2} + 3 y^{2})

6 y

Solution steps

\frac{\partial}{\partial y} (3 x^{2} + 3 y^{2})

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) + \frac{\partial}{\partial y} (3 y^{2})

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (3 y^{2}) = 6 y

= 0 + 6 y

Simplify

= 6 y

\frac{\partial}{\partial y} (\frac{3}{x ^{2} + y ^{2}})

\frac{d}{d x} (3 x^{3} (x^{2} + 4)^{4})

\int 9 - A^{2} d A

x = y^{2} - 2 y, x - y - 4 = 0

h^{^{'}}

What is (\partial)/(\partial y)(3x^2+3y^2) ?
The answer to (\partial)/(\partial y)(3x^2+3y^2) is 6y